Python 構建URL

Python requests模塊可以幫助構建URLS并動態處理URL值。可以以編程方式獲取URL的任何子目錄，然后可以用新值替換其中的一部分以構建新的URL。

建立網址

下面的示例使用urljoin在URL路徑中獲取不同的子文件夾。urljoin方法用于將新值添加到基本URL。

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.090948.com
# Date : 2020-08-25
from requests.compat import urljoin
 base='https://stackoverflow.com/questions/3764291'
 print urljoin(base,'.')
 print urljoin(base,'..')
 print urljoin(base,'...')
 print urljoin(base,'/3892299/')
 url_query = urljoin(base,'?vers=1.0')
 print url_query
 url_sec = urljoin(url_query,'#section-5.4')
 print url_sec
  
 

執行上面示例代碼，得到以下結果：

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.090948.com
# Date : 2020-08-25
https://stackoverflow.com/questions/
 https://stackoverflow.com/
 https://stackoverflow.com/questions/...
 https://stackoverflow.com/3892299/
 https://stackoverflow.com/questions/3892299?vers=1.0
 https://stackoverflow.com/questions/3892299?vers=1.0#section-5.4
  
 

分割網址

URL也可以分為多個主要地址。如下所示，使用urlparse方法分隔用于特定查詢的附加參數或附加到URL的標記。

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.090948.com
# Date : 2020-08-25
from requests.compat import urlparse
 url1 = 'https://docs.python.org/2/py-modindex.html#cap-f'
 url2='https://docs.python.org/2/search.html?q=urlparse'
 print urlparse(url1)
 print urlparse(url2)
  
 

執行上面示例代碼，得到以下結果：

 
# Filename : example.py
# Copyright : 2020 By Codebaoku
# Author by : www.090948.com
# Date : 2020-08-25
ParseResult(scheme='https', netloc='docs.python.org', path='/2/py-modindex.html', params='', query='', fragment='cap-f')
 ParseResult(scheme='https', netloc='docs.python.org', path='/2/search.html', params='', query='q=urlparse', fragment='')